There are 8 members on a board of directors. If they must form a subcommittee of 3 members, how many different subcommittees are possible

56 possible different subcommittees

Step-by-step explanation:

This is a combination problem.

In combination probability, the formula is;

nCr = n!/((n - r)! × r!)

Now, out of the 8 members on the board of directors, they now want to form a subcommittee of 3 members.

Thus, the different subcommittees possible is given by;

8C3 = 8!/((8 - 3)! × (3!)) = 56

Thus, there are 56 possible different subcommittees

17

step-by-step explanation:

51/3=17

thus 17 is your answer.