. A 0.660 kg ball is dropped from rest from the top of a building and falls for 5.65 seconds. How tall was the building? [Neglect friction. Assume on or near
the Earth's surface.]

The height of the building is 156.42 m

Step-by-step explanation:

Given;

mass of the ball, m = 0.66 kg

time of fall, t = 5.65 s

initial velocity of the ball, u = 0

Apply the following kinematic equation to determine the height of the building;

h = ut + ¹/₂gt²

h = ¹/₂gt²

h = ¹/₂ x 9.8 x 5.65²

h = 156.42 m

Therefore, the height of the building is 156.42 m

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.