In a rectangle KLMN, the diagonals KM and LN intersect at O. (i) If KO = 4y + 6 and ON = 3y + 11, find the lengths of its diagonals. (ii) If ∠NKM = 32°, find ∠KON and ∠KMN. GUYS, IT'S VERY URGENT. I HAVE TO SUBMIT TOMORROW. PLS ANS. PLS DON'T GIVE WRONG ANSWERS

1). Length of diagonals = 52

2). m∠KON = 103°, m∠KMN = 45°

Step-by-step explanation:

KLMN is a rectangle.

Diagonals KM and LN intersect at point O.

1). Since, diagonals of the rectangle equally bisect each other.

   KM = 2(KO)

   KM = 2(4y + 6)

   And LN = 2(ON)

   LN = 2(3y + 11)

   Since, length of diagonals of a rectangle are equal in measure.

   2(4y + 6) = 2(3y + 11)

   4y + 6 = 3y + 11

   4y - 3y = 11 - 6

   y = 5

   Therefore, length of diagonals = 2(3y + 11)

                                                       = 2(15 + 11)

                                                       = 52 units

2). m∠NKM = 32°

    Since, m∠KNM = 90° [internal angle of a rectangle]

    And diagonal LN bisects this angle,

    m∠KNO = 45°

    In ΔKNO,

    m(∠NKM) + m(∠KNO) + m(KON) = 180°

    32° + 45° + m∠KON = 180°

    m∠KON = 180° - 77°

                   = 103°

    Since, m∠KMN = (m∠LMN)

    m∠KMN = = 45°

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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