A 34-year-old woman has a maximum heart rate of 175 bpm. She plans an exercise program so that her heart rate will be between 80% and 90% of her maximum heart rate for at least 30 minutes a day, 3 days a week. Calculate the desired range of heart beats per minute for this exercise program

The desired range is from 141 bpm to 157 bpm

Step-by-step explanation:

Given that the maximum heart rate = 175 bpm.

She plans an exercise program to reach the desired heart rate which is in the range of 80% and 90% of the maximum heart rate.

So, the lower limit of the desired heart rate = 80% of the maximum heart rate

=\frac{80}{100}\times 175= 140 bpm

and the upper limit of the desired heart rate = 90% of the maximum heart rate

=\frac{90}{100}\times 175= 157.5 bpm

So, mathematically, the desired range is between 140 bpm and 157.5 bpm.

The heart-beats per minute should be a counting number, so, round the upper limit to the lower integral value to be within the range.

Hence, the desired range is from 141 bpm to 157 bpm.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.