According to a company's website, the top 15% of the candidates who take the entrance test will be called for an interview. You have just been called for an interview. The reported mean and standard deviation of the test scores are 70 and 7, respectively. If test scores are normally distributed, what is the minimum score required for an interview?

The minimum score required for an interview is 77.252

Step-by-step explanation:

We solve this using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Top 15% of the candidates is a ranking that is equivalent to = 100 - 15% = 85th percentile.

The z score of 85th percentile = 1.036

Mean = 70

Standard Deviation = 7

Minimum score = raw score = ???

Hence:

1.036 = x - 70/7

Cross Multiply

1.036 × 7 = x - 70

7.252 = x - 70

x = 70 + 7.252

x = 77.252

The minimum score required for an interview is 77.252

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x