A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p. M. Three hours later, the fish was at a depth that is LaTeX: 3\frac{1}{4}3 1 4feet below where it was at 1: 00 p. M. What rational number represents the position of the fish with respect to the water's surface at 4:00 p. M.?

feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 feet

                                                                             =   feet

The depth of the fish to its initial position at 4:00 pm = 3 feet

                                                                              = feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =   +

                                        =

                                         =

The position of the fish with respect to the water's surface at 4:00 pm is feet.

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

the answer is d. (1.2, -4.7) on edgn

hope this !