Analyze tables use the table that shows the percents of blood types of 145 donors during a recent blood drive a. find how many donors had type b blood. Round to the nearest whole number if necessary _

b. How many donors did not have type O blood? Round to the nearest whole number if necessary _

c. Which blood type has less than 10 donors?

blood type percent
O 45
A 40
B 11
AB. 4

a. 16

b. 80

c. Blood type AB

Step-by-step explanation:

Given:

O = 45%

A = 40%

B = 11%

AB = 4%

Total number of donors = 145

a. No. of donors that had type B blood =

Type B blood donors ≈ 16

b. No. of blood donors without blood type O =

Those without blood type O ≈ 80

c. Find the number of people that had type AB:

Type AB = ≈ 6. This is less than 10 donors.

Therefore, blood type AB had less than 10 donors.

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)