Can someone plz help me with dos plz

Part (i)

Reason:

Angle CBA is a right angle (thales theorem), so angle DBA must add to DBC to get 90 degrees. In other words, we solve x+46 = 90 to get x = 44.

Part (ii)

Reason:

Both inscribed angles DAC and DBC subtend the same arc (minor arc DC), so the inscribed angles are congruent.

Part (iii)

Reason:

Angle BDC is 28 degrees since angle BAC is also 28 degrees (similar reasoning as part ii above). Let y = angle BCD

Focus on triangle BCD. The three interior angles add to 180

B+C+D = 180

46+y+28 = 180

y+74 = 180

y = 180-74

y = 106

Then subtract 180 from this to get the exterior angle BCE

angle BCE = 180-(angle BCD)

angle BCE = 180-y

angle BCE = 74

Or as a shortcut, you could use the remote interior angle theorem

angle BCE = (angle BDC) + (angle DBC)

angle BCE = (28) + (46)

angle BCE = 74

what is all that apply?