A Cessna 172 plane that is used to transport up to four VIPs is 2 km in the air if the potential energy of the VIP plane with three VIPs on board is 860 J what is the combined mass of the Cessna and passengers

0.0438 kg

Step-by-step explanation:

We are given;

Potential energy; U = 860 J

Height; h = 2 km = 2000 m

Formula for potential energy is;

U = mgh

Where g is acceleration due to gravity = 9.81 m/s²

Thus;

860 = m × 9.81 × 2000

m = 860/(9.81 × 2000)

m = 0.0438 kg