Admission to a local aquarium is $10 for adults and $7 for children. The aquarium
collected $6,549 from the sale of 783
tickets. Find the number of adult tickets and
children tickets that were sold.

First, let's define variables:

A = adults

C = children

Okay, now that's done, time to set up the two equations required to solve:

10a + 7c = 6549

a + c = 783

One way you can solve this is to set up the second equation to isolate a variable. For example,

a = -c + 783

Using this, we can plug it into the first equation and solve for c.

10(-c+783) + 7c = 6549

-3c = -1281

c = 427

Now, use the value of 427and plug it in either equation to solve for a.

a + 427 = 783

a = 356

356 adult tickets were sold, and 427 children tickets were sold.

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.