Please Solve
3/5 (2m-10)=2/3m+10

m = 30

Step-by-step explanation:

3/5 (2m-10)=2/3m+10

Distribute

6/5 m - 6 = 2/3m +10

Subtract 2/3 m from each side

6/5 m - 2/3 m - 6 = 2/3m -2/3m +10

6/5 m -2/3m - 6 =  10

Add 6 to each side

6/5 m -2/3m - 6+6 =  10+6

6/5m -2/3m = 16

Get a common denominator of 15

18/15 m - 10/15 m  =16

8/15 m = 16

Multiply each side by 15/8

15/8 *8/15 m = 16*15/8

m = 30

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

lo.lll

step-by-step explanation: