Solve for p. 3+|1+p|=12

3+1+p=12

add the numbers

4+p=12

now we do the same thing only different way ok

3+1=4

To add the numbers using a number line , start from zero

Since 3 is positive, Move the points 3 units to the right

since 1 is positive, move the point 1 unit to the right

The result is 4

4+p=12

move constant to the right hand side and change its sign

p=12-4

Subtract the numbers

p=8

now we do the same thing only different way

12-4=12+(-4)=8

p=8

That's it. hope it wasn't too hard to understand?

PLEASE MARK ME AS BRAINLIEST

To write the subtraction as an addition, first copy the number 12

change the subtraction sign to an addition sign

Write the opposite of 4 as the second term of the sum

to add the numbers using a number line, start from zero

Since 12 is positive, move the point 12 units to the right

Since -4 is negative, move the point 4 units to the left

The result is 8

1 is c

2 is a

3 is a

step-by-step explanation: