100^(3-4x)/(2x+1) is less than or equal to 0.01^(5x-8)/(2x+1)

domain: 2x+1 not equal to zero, then x not equal to -1/2

Set 2x+1>0

then x>-1/2

100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)

100^(3-4x)<=0.01^(5x-8)

(10^2)^(3-4x)<=[10^(-2)]^(5x-8)

10^[2*(3-4x)]<=10^[(-2)*(5x-8)]

10^(6-8x)<=10^(16-10x)

6-8x<=16-10x

2x<=10

x<=5

combine x>-1/2 and x<=5

then - 1/2<x<=5

Set 2x+1<0

then x<-1/2

100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)

100^(3-4x)>=0.01^(5x-8)

(10^2)^(3-4x)>=[10^(-2)]^(5x-8)

10^[2*(3-4x)]>=10^[(-2)*(5x-8)]

10^(6-8x)>=10^(16-10x)

6-8x>=16-10x

2x>=10

x>=5

combine x<-1/2 and x>=5

, then x does not exist while 2x+1<0

so answer is - 1/2<x<=5

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.