Fully simplify.
(-2V-49)(5V-100)

(-2v-49)x(5v-100)

Multiply each term in the first parentheses by each term in the second parentheses (foil)

-2vx5v-2vx(-100)-49x5v-49 x (-100)

calculate the product

-10v²-2v x(-100)-49x5v-49 x(-100)

-2vx5v

Multiply the numbers

-10v x v

the same of the other one ok is different how i am doing

-2vx5v

If a term doesn't have an exponent , it is considered that the exponent is 1

-10v^ 1 x v

-10v^1 xv^1

Multiply the terms with the same base by adding their exponents

-10v^1 x v^1

-10v^1+1

to add the numbers using a number line, start from zero

1+1=2

Since 1 is positive, move the point 1 unit to the right

The result is 2

-10v^2

That's it . Hope it wasn't too hard to understand?

PLEASE MARK ME AS BRAINLIEST

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

where's the diagrams?