True or false: an cubic function may have 3 irrational zeros

The key word here is "may" meaning that we could easily have 3 rational roots as well. An example of a cubic having 3 irrational roots would be

(x-1)(x-2)(x-3) = x³ - 6x² + 11x - 6

This has the rational roots x = 1, x = 2, x = 3.

However, we could easily replace 1,2,3 with any irrational numbers we want. So that's why the statement "a cubic has three irrational roots" is sometimes true.

In some cases, a cubic may only have 1 real root and the other 2 roots are imaginary.

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation:

in english this is

ex.15 pag.85 create. write in ten lines the continuation of the ballad of the five motanasi, using verbs to the imperfect and to the perfect compound. five stars

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