Mrs. Beno wrote this equation on the board and asked, “Is this a true equation?” \left(x+y\right)^2=x^2+y^2(x+y)
2
=x
2
+y
2

Nigel said sometimes it is and sometimes it is not and broke the equation into 4 cases. For each case determine whether the equation is true or false and explain your reasoning.

Item at position 6
6
0 points

CASE 1:

x\ne0, y\ne0x

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!

my computer is slow i can not see it sorry

25/32 is the simplest form