A line has gradient 5. M and N are two points on this line.
M is the point (x, 8) and N is the point (k, 23).
Find an expression for x in terms of k.

Pls help it’s emergency!!

x = k - 3

Step-by-step explanation:

Given parameters:

  Gradient of the line = 5;

Coordinates; M(x, 8)

                       N(k, 23)

Solution:

If we use the expression for finding the slope of the line, we can solve this problem;

     Slope  =

    where

    x₁ = x    y₁ = 8

    x₂ = k    y₂ = 23

Input the parameters:

       5  =

          15 = 5(k - x)

           3= k- x

           k - x = 3

 Express x in terms of k;

          -x = 3 - k

Multiply through by -1;

          x = -3 + k

          x = k - 3

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: