A rocket is launched from a tower. The height of the rocket, why in feet, is related to the time after lunch, eggs in seconds, by the given equation. Using the equation, to find the time that the rocky with the ground, to the nearest hundredth of second. Y=-16x^2+187x+93

the answer is d. (1.2, -4.7) on edgn

hope this !

answer:

a=9

step-by-step explanation: lmk if you need a explanation

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube