If adult females are randomly selected, find the probability that they have pulse rates with a mean between 70beats per minute and 82beats per minute.

This question is incomplete.

Complete Question

Assume that females have pulse rates that are normally distributed with a mean of u = 76.0 beats per minute and a standard deviation of 12.5 beats per minute. If 1 adult female is randomly selected, find the probability that her pulse rate is between 70 beats per minute and 82 beats per minute. The probability is (Round to four decimal places as needed.)

0.3688

Step-by-step explanation:

The formula for calculating a z-score when given a random sample of numbers is is z = (x-μ)/σ/√n

where x is the raw score,

μ is the population mean, and

σ is the population standard deviation.

mean = 76.0 beats per minute and a standard deviation = 12.5 beats per minute.

n = number of random samples = 1

For 70 beats per minute

z = 70 - 76/12.5/√1

z = -0.48

Probability value from Z-Table:

P(x = 70) = 0.31561

For 82 beats per minute.

z = 82 - 76/12.5/√1

z = 0.48

Probability value from Z-Table:

P(x = 82) = 0.68439

The probability that her pulse rate is between 70 beats per minute and 82 beats per minute.

P(x = 82) - P(x = 70)

0.68439 - 0.31561

= 0.36878

≈ 0.3688

christopher is 272,195 year old

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺