The red-tailed tropic bird, Phaethon rubricauda, is an extremely rare sea bird that nests on several islands of the Queensland coast of Australia. As part of a conservation e ort to manage these endangered birds, every nesting pair was measured and weighed. Below are the body weights of these birds (in kg). Female 2.45 2.57 2.81 2.37 2.01 2.50 2.32
Male 2.86 2.65 2.75 2.60 2.30 2.49 2.84

Required:
a. Determine the following descriptive characteristics for the weights of the females: mean, variance, and standard deviation. Is this a sample or population? Again, pay attention to number of decimal places and appropriate units.
b. Determine the mean, variance, and standard deviation for the male weights.

This is a population

a) Female

Mean : 2.432857143kg

Variance: 0.05162040817kg

Standard deviation: 0.2272012504kg

b) Male

Mean : 2.641428571kg

Variance : 0.03432653062kg

Standard deviation: 0.1852742039kg

Step-by-step explanation:

a. Determine the following descriptive characteristics for the weights of the females: mean, variance, and standard deviation. Is this a sample or population? Again, pay attention to number of decimal places and appropriate units.

a) Female: 2.45 2.57 2.81 2.37 2.01 2.50 2.32

Mean

The formula = Sum of term/ Number of terms

Mean = 2.45 + 2.57 + 2.81 + 2.37 + 2.01 + 2.50 + 2.32/7

17.03/7

= 2.432857143kg

Variance

This is a population

Hence: The formula for Population variance =

= (X - Mean)²/N

Where N = Number of terms = 7

= (2.45 - 2.432857143)² + (2.57 -2.432857143)² + (2.81 -2.432857143)² + (2.37- 2.432857143)²+ (2.01 - 2.432857143)²+ (2.50 - 2.432857143)² + (2.32 - 2.432857143)² /7

= 0.0002938775509 + 0.01880816325 + 0.1422367347 + 0.003951020409 + 0.1788081633 + 0.004508163265 + 0.0127367347/7

= 0.3613428572/7

= 0.05162040817kg

Standard Deviation

Formula = √Variance

= √0.05162040817

= 0.2272012504kg

b. Determine the mean, variance, and standard deviation for the male weights

Male 2.86 2.65 2.75 2.60 2.30 2.49 2.84

Mean

The formula = Sum of term/ Number of terms

= 2.86 + 2.65 + 2.75 + 2.60 + 2.30 + 2.49 + 2.84/7

= 18.49/7

= 2.641428571 kg

Variance

= ( 2.86 -2.641428571)² + (2.65 - 2.641428571)² + (2.75 -2.641428571)² + (2.60 +2.641428571)² + (2.30 - 2.641428571)² + (2.49+2.641428571)² (2.84 + 2.641428571)²/7

= 0.0477734694 + 0.00007346938775 + 0.01178775511 + 0.001716326531 + 0.1165734694 + 0.02293061224 +! 0.03943061226/7

= 0.2402857143/7

= 0.03432653062kg

Standard Deviation

= √Variance

= √0.03432653062

= 0.1852742039kg

yeet

step-by-step explanation:

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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