Rasha and Scott went to a bakery. Rasha bought 4 plain bagels and 2 chocolate donuts for a total of $8.70. Scott bought 3 chocolate donuts for a total of $2.55.
What is the cost of one plain bagel at the bakery?

Step-by-step explanation:

Let b = bagels , d = donuts

Rasha bought 4 plain bagels and 2 chocolate donuts for a total of $8.70

We can write this as :

4b + 2d = 8.70

Scott bought 3 chocolate donuts for $2.55

3d = 2.55

First, let's find out the cost of 1 donut.

To do this, divide 2.55 by 3.

1d = 2.55/3 =0.85  (1 donut costs $0.85)

Substitute the value of d ( d = 0.85 ) into the equation 4b + 2d = 8.70

4b + 2d = 8.70

4b + 2 (0.85) = 8.70

4b + 1.7 = 8.70

Subtract 1.7 from both sides.

4b = 8.70 - 1.7

4b = 7

Divide both sides by 4 to find how much one bagel costs.

b = 7/4 = 1.75

Therefore, one bagel costs $1.75

1/5x+9 2/5y+7

step-by-step explanation: