Write an equation of a line that passes through the point (5,1) and is parallel to the line y= (-3/5)x -3

y = (-3/5)x + 4

Step-by-step explanation:

Parallel lines have the same slope.

So the slope to the other line would be -3/5 as well.

Slope-intercept form is y = mx + b where m is the slope.

So you substitute the slope in making it y = (-3/5)x+b.

To find b, the y-intercept, you have to plug in the point for y and x in it. So you use the point (5,1) for it. That would get to 1 = (-3/5)5 + b.

To simplify that, it would get to 1 = -3 + b

Then you add 3 on both sides getting to b = 4.

Then you substitute b in, getting y = (-3/5)x + 4.

Hope this helped! If not, please let me know! <3

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula