Lines s, t, and u are perpendicular bisectors of the sides of APGH and meet at J. If JG - 2x+ 2, JH - 2y-4, JF-8 and HI - 32-3, find x, y, and z.

Ox= 5, y = 2, z = 2

O x = 2, y = 7,2 = 2

x = 3, y = 6,2 = 4

x = 6.) = 3,2 = 4

x = 3, y = 6, z = 4

Step-by-step explanation:

If lines s, t, and u are perpendicular bisectors of the sides of APGH and meet at J, then JG = JH = JF = HI

Given

JG - 2x+ 2

JH - 2y-4

JF-8 a

HI - 3z-3,

Hence 2x+2 = 2y-4 = 3z-3 = 8

This means that

2x+2 = 8

2x = 8-2

2x = 6

x = 3

Also, 2y-4 = 8

2y = 8+4

2y = 12

y = 6

And 3z-3 = 8

3z = 8+3

3z = 11

z = 11/3

z = 3.67 ≈ 4

Hence x = 3, y = 6,z = 4

d

gimmee one of those gold crowns!

~coco

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^