When did humans start to separate brain and heart As if they could stay alive alone?

Flip it around the other way
If they were apart and you had no power start
Or no database
Only your shell remains
What fun is it to be so calculated
Or be taken advantage of 'cause your heart's too trusting?
Silent expressed, push my head into my chest
Bind them up, forever wed
"Don't drift too far," they said

hreryryrranswer:

step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.

answer: c. is your answer

step-by-step explanation: get me a black leather coat

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.