Solve:
12 + 5 + 3’2 x 10 - 5 =
(12 + 5) + 3'2 x (10 – 5) =

Hi :)

12 + 5 + 3^2 x 10 - 5 = 102

(12 + 5)+ 3^2 x (10 - 5) = 62

12 + 5 + 3^2 x 10 - 5

Add 12 and 5 to get 17
17 + 3^2 × 10−5

Calculate 3 to the power of 2 and get 9
17 + 9 × 10 − 5

Multiply 9 and 10 to get 90
17 + 90 − 5

Add 17 and 90 to get 107
107−5

Subtract 5 from 107 to get 102

(12 + 5)+ 3^2 x (10 - 5)

Add 12 and 5 to get 17
17 + 3^2 x (10 - 5)

Calculate 3 to the power of 2 and get 9
17 + 9 x (10−5)

Subtract 5 from 10 to get 5
17+ 9 × 5

Multiply 9 and 5 to get 45
17+45

Add 17 and 45 to get 62.

Hope this helps :)

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!