What are four consecutive integers with the sum of 318

Consecutive integers are 1 apart
they are
x,x+1,x+2,x+3

sum is 318

x+x+1+x+2+x+3=318
4x+6=318
minus 6 from both sides
4x=312
divide both sides by 4
x=78

x+1=79
x+2=80
x+3=81

they are
78,79,80,81

7.1 is in between -8 and -7 because -7. 1 is equal to -7. 10 and that number is 10 numbers away from the number 7. ur welcome!