Three times a number increased by one is between negative eight and seven find all the numbers. All the numbers that makes the statement true are given by?

Please hurry this is on my exam

This is about absolute value inequalities.

The set of possible values of x that make the statement true are; x = {-2, -1, 0, 1}

We are told that when it is multiplied by 3 and 1 added to it, it is between - 8 and 7. This means it is greater than -8 but less than 7.

Thus;

3x + 1 > -8  - - - (eq 1)

3x + 1 < 7  - - - (eq 2)

3x + 1 > -8

Subtract 1 from both sides to get;

3x > -9

x > -9/3

x > -3

3x + 1 < 7

Subtract 1 from both sides to get;

3x < 7 - 1

3x < 6

x < 6/3

x < 2

Thus, we can write that;

-3 < x < 2

Thus, the set of possible values of x are; x = {-2, -1, 0, 1}

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step-by-step explanation:

where are the choices?