24. Janet and Jack are walking in a two-day event to raise money for charity. Janet asks a friend for a $7.50 donation, plus $0.10 for each mile she
walks. Jack asks a friend for a $5.50 donation, plus $0.15 for each mile
he walks. At how many miles of walking would Janet and Jack collect the
same amount of money?

40 miles walk

Step-by-step explanation:

Let the miles walked by both of them be x at which money collected by same

for Janet

Fixed donation  asked = $7.50

money asked for walking 1 mile = $0.10

money made by Janet if he walks x miles = x*$0.10 = $0.10x

Total money collected by Janet = Fixed donation  asked + money made by Janet if he walks x miles

Total money collected by Janet =7.50 + 0.10x

For Jack

Fixed donation  asked = $5.50

money asked for walking 1 mile = $0.15

money made by Janet if he walks x miles = x*$0.15 = $0.15x

Total money collected by Jack = Fixed donation  asked + money made by Jack if he walks x miles

Total money collected by Jack =5.50 + 0.15x

we have to find miles at which money collected by both of them be same

and we have decided that it it as x mile walk then

Total money collected by Janet = Total money collected by Jack

7.50 + 0.10x = 5.50 + 0.15x

=> 7.50 - 5.50 = 0.15x - 0.10x

=> 2 = 0.05x

=> x = 2/0.05 = 40

Thus, at 40 miles walk money collected by both of them will be same

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier