TEST 1) ERROR ANALYSIS: Identify and correct the error in describing the transformation of the parent
function.

Sadly the question is incomplete, so we can not see the described transformation of the parent function, thus we can't see the error in that description.

What we can do is describe the transformation shown here.

Here we can see the parent function:

f(x) = x^2

This function opens upwards, so what we see in the graph is this function reflected across the horizontal axis (the x-axis). So the transformation is just a reflection across the x-axis.

(notice that it passes through (-1, -1) and (1, -1), so there is no dilation nor contraction)

For a general function f(x), a reflection across the x-axis is just:

g(x) = -f(x)

So here the transformed function is:

g(x) = - x^2

If you want to learn more, you can read:

link

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

80 the answer is 80

step-by-step explanation: