One night a theater sold 548 movie tickets. An Adult’s ticket costs $6.50 and a child’s ticket cost $3.50. In all $2881 was taken in. How many of each kind of ticket were sold?

Step-by-step explanation:

let x be the number of adults and y the number of childrens

x+y=548 people because thats the whole number of sold tickets

and

6.50*x+3.50*y=2881 dollars in total

let separate x from the first formula

x=548-y

and replace it at the second equation

6.50*(548-y)+3.50y=2881

6.50*548-6.50y+3.50y=2881

3562-3y=2881

3y=681

y=227

so x=548-y=548-227=321

there were sold 321 adult tickets and 227 child's tickets.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.