Six stand up comics, a, b, c, d, e, and f, are to perform on a single evening at a comedy club. the order of performance is determined by random selection. find the probability that:
1. comic d will perform first.
2. comic b will perform fifth and comic a will perform last.
3. the comedians will perform in the following order: d, b, a, c, f, e
4. combic f or combic e will perform third.

Find the probability that 
1.Comic D will perform first

D _ _ _ _ _
 We can fill the 5 blanks with the 5 letters A, B,C,E,F in 5! = 120 ways
The probability of that is 120 ways out of 720 or 120/720 or 1/6. 

2. Comic B will perform fifth and Comic A will perform last
_ _ _ _ B A
We can fill the 4 blanks with the 4 letters C,D,E, F in 4! = 24 ways.
The probability of that is 24 ways out of 720 or 24/720 or 1/30.

3. The comedians will perform in the following order D, B, A, C, F, E
There is just 1 way that can happen. The probability of that is 1 way out of 720 or 1/720.

4.Comic F or E will perform third.
_ _ F _ _ _
There are 5! = 120 ways to fill those 5 blanks with the letters A,B,C,D, E.
In addition to those, there are another 5! = 120 ways to fill these 5 blanks _ _ E _ _ _ with the letters A,B,C,D,F. That's 2(5!) = 2(120) = 240 ways.
The probability of one of those is 240 ways out of 720 or 240/720 or 1/3.

For me i think it'll land on blue