Brandon has 36000 to invest and wants to earn 5% interest per year. He will put some of the money into an account that earns 4.4% interest per year and the rest into an account that earns 6% interest per year. How much money should he put into each account so that he earns 5% annually

The money in an account that earns 4.4% interest per year = 22500

The rest into an account that earns 6% interest per year = 13500

Step-by-step explanation:

Interest = Principal × Rate × Time

Let x = money saved in account A

Let y = money saved in account B

Brandon has 36000 to invest and wants to earn 5% interest per year

x + y = 36000 Equation 1

x = 36000 - y

He will put some of the money into an account that earns 4.4% interest per year and the rest into an account that earns 6% interest per year.

Hence:

4.4% × x × 1 + 6% × y × 1 = 36000 × 5% × 1

0.044x + 0.06y= 1800 Equation 2

Substitute 36000-y for x in Equation 2

0.044(36000 - y) + 0.06y = 1800

1584 -0.044y + 0.06y = 1800

-0.044y + 0.06y = 1800 - 1584

0.016y = 216

y = 216/0.016

y = 13500

Note that:

x = 36000 - y

x = 36000 - 13500

x = 2250

Therefore,

The money in an account that earns 4.4% interest per year = 22500

The rest into an account that earns 6% interest per year = 13500

im pretty sure its

(8,15)

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: