A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 10 minutes. Air traffic control approved a new flight plan that will allow her to arrive three times faster than she calculated in her original flight plan. Let x represent the time, in minutes, of her original flight. Create an equation that can be used to predict the number of minutes after 4:00 pm she will arrive at her destination. y equals one third times x plus 10 y = 3x + 10 y equals one third times x minus 10 y = 3x − 10

a. y equals one third times x plus 10

= y = 1/3(x) + 10

Step-by-step explanation:

Let us represent:

Let the original final plan = x

Let the current flight plan = y

The initial time of departure = 4.00pm

Her flight was then delayed for 10 minutes

We are told in the question that:

The current flight plan allows her arrive at her destination three times faster.

This means y= (1/3)x

y = x/3

Hence the equation generated =

y = x/3 +10

y = 1/3(x) + 10

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)