College Alisha is putting cheese cubes and crackers onto small plates. She has 24 cubes of cheese and 40 crackers. She want both cheese and crackers on each plate and each plate must have the same number of cheese cubes and the same number of crackers. What is the greatest number of plates she can make using all the cheese and crackers.

there will be 8 plates each having 3 cubes of Cheese and 5 crackers

Step-by-step explanation:

To determine the greatest number of plates she can make using all the cheese and crackers, find the highest common factor of 24 and 40

24 = 2, 3, 4, 6, 8, 12, 24

40 = 2, 4, 5, 8, 10, 20, 40

Highest common factor of 24 and 40 is 8

24 cubes of cheese / 8 plates = 3 cubes of cheese per plate

40 crackers / 8 plates = 5 crackers per plate

So, there will be 8 plates each having 3 cubes of Cheese and 5 crackers

only 10/60 isn't equivalent

hope this : )

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point