At a birthday party, 5 boys and 3 girls are seated in a row. How many different arrangements are possible if there are no restrictions?

Step-by-step explanation:

There are 5 boys and 3 girls

With no restrictions, 8 people can seat in 8! ways

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2