Can someone PLEASE show me how to do this! If f (x) = x^2 + 3x +2/ x +3, then f’ (x) =

c

Step-by-step explanation:

The equation =( denominater * derivative of numerator - numerator * derivative of denominator) / denominator ^2

so the qstn is (x^2 + 3x +2) / (x+3)

apply the values as the above eqtn states

ie,[ (x+3) * derivative of (x^2 +3x + 2)] - [( x^2 +3x + 2) *derivative of (x+3)] /

(x+3)^2

derivative of numerator, (x^2 +3x + 2) is 2x+3

" of denominator, (x+3) is 1

so we get

[(x+3)* (2x + 3 ) - (x^2 +3x + 2) *1 ] / (x+3)^2

open the brackets

[ 2x^2 + 3x + 6x + 9 - x^2 +3x + 2 ] / (x+3)^2

subtract similar terms and we get the final answer in option c

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

mia khalifa

step-by-step explanation: