A box in the shape of a rectangular prism, with dimensions 12 inches by 18 inches by 12 inches, can hold exactly 12 cubes measuring 6 inches on each side. If the length and width of the base are doubled, how many cubes could the new box hold?

18
24
48
96

 48 cubes in the new box

Step-by-step explanation:

Doubling the length and the width is 2×2, so 4 times the original capacity.

4×12 = 48

It is not necessary to compute the volume. The dimensions could be anything. It's the number of cubes that count.

understand that i don't know the answers

will someone answer his question

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -