The lengths of a professor's classes has a continuous uniform distribution between 49.2 min and 55.5 min. One class is randomly selected. If P(x > c) = 0.488 , find c

52.4 min

Step-by-step explanation:

100% of the times are between 49.2 min and 55.5 min.

48.8% of the times are between x and 55.5 min.

Write a proportion:

(55.5 − 49.2) / 1 = (55.5 − x) / 0.488

0.488 (55.5 − 49.2) = 55.5 − x

3.0744 = 55.5 − x

x = 52.4256

Rounded to the tenths place, the time is 52.4 min.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.