I don’t know how to solve it please help

when x=0 then f(x) = -2

when x=1 then f(x) = 3

when x=2 then f(x) = 8

Step-by-step explanation:

you just plug in the x value given to you into the equation (which is 5x-2) so for example:

if x = 0 then:

5x-2 is instead 5(0)-2 which means you multiply 5 and 0 and then substract 2 because you have to follow PEMDAS

PEMDAS is (Parenthesis, Exponents, Multiplication, Division, Addition, Substraction) which is the order of priority to be solved, so you first solve parenthesis, then exponents, then you multiply or divide, and then you add or substract

easy way to remember PEMDAS: Please Excuse My Dear Aunt Sally, OR Please End My Depression And Suffering (my favorite way to remember, don't take that seriously tho >_>)

so because you have to multiply before subtracting you multiply 5 and 0, you get 0, and then you take away 2 which is -2

remember to just plug in your values and then do PEMDAS

hope you learned something :P

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2