What is the remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2? A. -23
B. 23
C. -3
D. 3

The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

A polynomial is an expression consisting of the operations of addition, subtraction, multiplication of variables.

Polynomial based on degree is linear, quadratic, cubic.

The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial x - a, the remainder of is to f(a)

Given that f(x) = 2x⁴ + x³ - 8x - 1 is divided by x - 2

x - 2 = 0

x = 2

f(2) = 2(2)⁴ + (2)³ - 8(2) - 1 = 23

Hence The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

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By the remainder theorem, dividing by leaves a remainder of , which is

which makes B the correct answer.

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

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