The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. what is the point-slope form of the equation for this line? y – 13 = 5(x – 2) y 13 = 5(x 2) y – 2 = 5(x – 13) y 2 = 5(x 13

Slope intercept form of equation of a line is given by y = mx + c where m is the slope
Point slope form is given by y - y1 = m(x - x1); where (x1, y1) is any point on the line.
Required equation is y - (-13) = 5(x - (-2))
y + 13 = 5(x + 2)

Yes you are correct

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!