The larger of two numbers is twelve more than the twice smaller number. The sum of the numbers is 42. Find the two numbers . Please set up a , set up the equation , and then solve the equation .

             The smaller number:  a = 10

             The larger number is 32

Step-by-step explanation:

a - the smaller number

2a - twice the smaller number

2a+12   - twelve more than the twice smaller number (the larger number)

a + 2a+12  - the sum of the numbers

a + 2a+12 = 42

     -12              -12

          3a  =  30

          ÷3       ÷3

            a = 10

2a+12 = 2×10+12 = 20+12 = 32

Check:   10+32=42

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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