The path of an object launched above ground can be modeled by h(t)=-3t^2+30t+4 where h(t) represents the height in feet at any given time in seconds Prior to launch, the initial height of the object is feet After launch, the object reached its maximum height of feet in seconds The height of the object above the ground 10 seconds after it was launched is feet The object will strike the ground in seconds (round answer to nearest tenth)