The question is " find the zeros of each function by using the quadratic formula." h(x) = 3x^2-3x+3/4

Step-by-step explanation:

Quadratic formula goes as follows and , there is no plus or minus (+/- thingy) sign on here but use both plus and minus on the numerator where I switched the signs.

The equation you give is , to make it nice, multiply everything by 4 to cancel out the fraction and end up with . So a=12, b=-12, and c=3. Use these values and plug them into quadratic formula.

For the first formula I wrote, , you get = .

For the second formula, , you get = .

Always do quadratic formula for both plus and minus to get both zeros. However, in this case, the answer still remained positive. So the zero of this would be just  .

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step-by-step explanation:

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answer: your gay

step-by-step explanation:

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