Diego pays $4.50 for 3 pound of bananas and 2 pounds of oranges. One pound of oranges costs $0.75 more than one pound of bananas. Let b represent the price per pound of bananas . which equation represents the situation, and what is the price per pound of each fruit?

D. 3b + 2(b + 0.75) = 4.50; $0.60 per pound of bananas, $1.35 per pound of oranges

Step-by-step explanation:

Price per pounds of bananas = b

Price per pound of oranges = b + $0.75

Diego buys:

3 pounds of bananas = 3(b) = 3b

2 pounds of oranges = 2(b + 0.75)

Amount paid by Diego is expressed as:

3b + 2(b + 0.75) = 4.50

To find the price per pound of each fruit, use the equation above to find the value of b:

3b + 2b + 1.50 = 4.50

Combine like terms

5b + 1.50 = 4.50

5b + 1.50 - 1.50 = 4.50 - 1.50

5b = 3

5b/5 = 3/5

b = 0.6

Price per pound of banana = b = $0.6

Price per pound of oranges = b + $0.75

Plug in the value of b

= $0.6 + $0.75

= $1.35

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.