A submarine left Diego Garcia traveling east 5 hours before an aircraft carrier. The aircraft carrier traveled in the opposite direction going 10 km/h faster than the submarine for 2 hours after which time the ships were 110 km apart. Find the submarine's speed

Step-by-step explanation:

Let the submarine's speed be x km/h

the time taken by the submarine is given as 5 hours

the aircraft travels 10km/h faster than the submarine= 15km/h

time taken by the aircraft is 2hours

therefore the distance covered by both vehicles can be described using the expression below

we know that distance=velocity*time, so equating the two vehicles distance to 110km we have

5*x+15*2=110

5x+30=110

solving for x we have

5x=110-30

5x=80

divide both sides by 5 we have

x=80/5

x=40km/h

The submarine's speed is 40km/h

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0