PLEASE HELP I BEG 70 POINTS Part A: Explain how to sketch the graph of a curve that opens downwards and has only one x-intercept at (2.5,0).

Part B: Explain how to sketch the graph of a curve that opens upwards where the minimum value of the graph is (0,1).

Part C: Explain how to sketch the graph of a curve with the following characteristics.
• The graph opens downward.
• The y-intercept is (0,6).
The z-intercepts are (-1,0) and (3, 0).
• The maximum value of the function is located at the point (1,8).

Part A:

If a quadratic has only one x-intercept, then that is where the vertex lies. being that the vertex is the highest or lowest point in the quadratic. To sketch, it will open downwards with a single x-cept

Part B:

The graph will be above the x-axis. And having the vertex being at (0,1) as it says its the minimum value. All the minimum means is that its the lowest value of this given parabola.

Part C:

Plot the points of the y-intercept and z-intercepts. Then plot the maximum value is. Connect the dots.

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )