A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 119x + 73

Step-by-step explanation:

Given function

This is quadratic function  

It reaches the maximum value at vertex, which is calculated by the formula:

Substituting values

y-value of same point is

So maximum height is 294.3 ft

The equation we have is:

This is equation of a parabola that opens down.

To find the maximum point or the maximum height, we need to find the vertex of the parabola.

First, let's define variables:

A will be the coefficient of the x squared.

b is the coefficient of the x and

C is the independent term:

The vertex of will have the following x coordinate:

Substituting the values of a and b:

Solving the operations:

The next step is to substitute this x value into our equation to find the maximum height y:

Solving the operations:

Rounding to the nearest tenth (1 decimal place)

y=294.2

294.2 feet.

answer: kljdcdhjbdlchjad oac apoich a

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value