The length of a rectangular garden is 7 feet more than 5 times the width. If the perimeter of the garden is 272 feet, what are its dimensions? Round to the nearest
tenth, if necessary.

The dimensions of the garden is 21.5 ft by 114.5 ft

Step-by-step explanation:

Here, we want to find the dimensions of a rectangular garden.

From the question, we are told that the length is 7 feet more than 5 times the width.

Let the length be l and the width be w;

Thus, mathematically;

l - 7 = 5w

l = 5w + 7

Mathematically;

Perimeter of rectangle = 2(l + w)

Hence;

2(l + w) = 272

divide both sides by 2

l + w = 136

but l = 7 + 5w

7 + 5w + w = 136

7 + 6w = 136

6w = 136-7

6w = 129

w = 129/6

w = 21.5 ft

But,

l = 5w + 7

l = 5(21.5) + 7

l = 114.5 ft

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

answer are

step-by-step explanation: