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Mathematics, 10.10.2020 20:01 alexcontreras32

Solve the equation, keeping the value for x as an improper fraction. 2 3 x = βˆ’ 1 2 x + 5 1. Isolate the variable by adding 1 2 x to both sides: 1 2 x + 2 3 x = 5 2. Use the common denominator to add terms: 3 6 x + 4 6 x = 5 7 6 x = 5 3. Multiply by the reciprocal: 6 7 (7 6 )x = 5(6 7 ) x =

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Solve the equation, keeping the value for x as an improper fraction. 2 3 x = βˆ’ 1 2 x + 5 1. Isolate...
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